Upper Limit = Basic Size +ES = 50+0.025=50.025

Lower Limit = Basic Size + EI = 50+0.002 = 50.002

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**2) **Limits of 50 mm hole is ES=+0.025 and EI =+0.002 mm. The maximum and minimum hole sizes will be:

**Answer is:**

## Max. 50.025 mm ; Min. 50.002 mm

**Explanation:**

**Related Limits and Fits MCQ - Machinist(Set-1) with Answers**

**Answer is:**

### 21 classes of fits and 16 grades of tolerances

**Explanation:**

British standard limit system consists of 21 classes of fits and 16 grades of tolerances.

**Answer is:**

### 25.00 mm

**Explanation:**

A dimension is stated as Dia 25 H7 in a drawing. The lower limit is 25.00 mm.

For 25 H7 Tolerance Grade

Basic Size = 25.000 mm

ES = +21 Microns = 0.021 mm

EI = 0 Microns = 0.000 mm

Hence

Lower limit = Basic Size + EI = 25.000 + 0.000 = 25.000 mm

Upper Limit = Basic Size + ES = 25.000 + 0.021 = 25.021 mm

Hence A dimension is stated as Dia 25 H7 in a drawing. The lower limit is 25.000 mm.

**Answer is:**

### 0.04 mm

**Explanation:**

A dimension is stated as 25 +/-0.02 mm in a drawing. Then

Basic Size = 25.000 mm

Upper Tolerance = + 0.02 mm

Lower Tolerance = - 0.02 mm

Total Tolerance = 0.02 + 0.02 = 0.04 mm

**Answer is:**

### Tolerance

**Explanation:**

Tolerance is defined as the difference between the maximum and the minimum sizes allowed in manufactured components.