As per IE rule, caution notice shall be displayed on electrical equivalents/lines depending on the level of voltage. What type of caution notice shall be displayed on equivalent/line operating between 650 V to 33 kV ?

heat energy to electrical energy

400 watts

The power consumed by an appliance can be calculated using the formula:

P = I^2 * R

where P is the power in watts (W), I is the current in amperes (A), and R is the resistance in ohms (Ω).

In this case, the resistance of the appliance is given as 100 ohms and the current flowing through it is 2 amperes. Substituting these values in the above formula, we get:

P = 2^2 * 100 = 400 watts

Therefore, the power consumed by the appliance is 400 watts.

4.166 amperes

W=V x I
I= W/V
=1000/240
=4.166 amperes